HackerRank Day 10: Binary Numbers – 30 Days of Code

In this article, we will be solving HackerRank Day 10: Binary Numbers problem, part of 30 Days of Code. Majorly, we will use Python3 and Java15 to solve the problem.

Objective:

Today, we’re working with binary numbers. Check out the Tutorial tab for learning materials and an instructional video!

Task

Given a base-10 integer, n, convert it to binary (base-2). Then find and print the base-10 integer denoting the maximum number of consecutive 1‘s in n‘s binary representation. When working with different bases, it is common to show the base as a subscript.

Example

n = 125

The binary representation of 125₁₀ is 1111101₂. In base 10, there are 5 and 1 consecutive ones on two groups. Print the maximum, 5.

Input Format

A single integer, n.

Constraints

• 1 <= n <= 10⁶

Output Format

Print a single base-10 integer that denotes the maximum number of consecutive 1’s in the binary representation of n.

Sample Input 1

5

Sample Output 1

1

Sample Input 2

13

Sample Output 2

2

Explanation

Sample Case 1:

The binary representation of 5₁₀ is 101₂, so the maximum number of consecutive 1’s is 1.

Sample Case 2:

The binary representation of 13₁₀ is 1101₂, so the maximum number of consecutive 1’s is 2.

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You can find all the source code on my GitHub profile: https://github.com/uttammanani/HackerRank-30-Days-of-Code

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Solution Day 10: Binary Numbers in Python3

#!/bin/python3

import math
import os
import random
import re
import sys

if __name__ == '__main__':
    n = int(input().strip())
    numbers = str(bin(n)[2:]).split('0')
    lenghts = [len(num) for num in numbers]
    print(max(lenghts))

Solution Day 10: Binary Numbers in Java15

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

        int n = Integer.parseInt(bufferedReader.readLine().trim());
        
        char[] binary = Integer.toBinaryString(n).toCharArray();
        int tmpCount = 0;
        int maxCount = 0;
        for(int i = 0; i < binary.length; i++){
            tmpCount = (binary[i] == '0') ? 0 : tmpCount + 1; 
            if(tmpCount > maxCount){
                maxCount = tmpCount;
            }
        }
        System.out.println(maxCount);
        bufferedReader.close();
    }
}

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